To solve this problem, we need to calculate the energy radiated by a 100 kW transmitter in 1 hour.$\\$Given:$\\$• Power of the transmitter $P = 100$ kW$= 100 \times 10^3$ W$\\$• Time duration $t = 1$ hour$= 3600$ seconds$\\$The energy radiated can be calculated using the formula:$\\ E = P \times t \\$Substitute the given values:$\\ E = (100 \times 10^3) \times 3600 \\$Calculate:$\\ E = 100 \times 3600 \times 10^3 \\ E = 360000 \times 10^3 \\ E = 36 \times 10^7$ J$\\$Therefore, the energy radiated by the transmitter in 1 hour is $36 \times 10^7$ J.$\\$This corresponds to Option 1.