Kelvi

A resistance $R$ draws power $P$ when connected to an AC source. If an inductance is now placed in series with the resistance, such that the impedance of the circuit becomes $Z,$ the power drawn will be

medium

Alternating Current

2015

physics

$P \sqrt\frac{R}{Z}$

$P \left( \frac{R}{Z} \right)$

$\text {P}$

$P \left( \frac{R}{Z} \right)^2$

Explanation

To solve this problem, we need to understand how power is affected when an inductance is added in series with a resistance in an AC circuit. $\\$ Given: $\\$ • Resistance $R$ draws power $P$ when connected to an AC source. $\\$ • Impedance of the circuit becomes $Z$

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A resistance R R R draws power P P P when connected to an AC source. If an inductance is now placed in series with the resistance, such that the impedance of the circuit becomes Z, Z, Z, the power drawn will be

Explanation

Our AI powered practice platform can help you achieve your doctor dream.

A resistance $R$ draws power $P$ when connected to an AC source. If an inductance is now placed in series with the resistance, such that the impedance of the circuit becomes $Z,$ the power drawn will be