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Kelvi

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Which plot of ln k vs 1/T is consistent with Arrhenius equation?

easy

ChemicalKinetics

2024

chemistry

option

option

option

option

Explanation

To solve this problem, we need to understand the Arrhenius equation: $\newline k = A e^{-\frac{E_a}{RT}} \newline$

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Taking the natural logarithm of both sides, we get:

\newline \ln k = \ln A - \frac{E_a}{R} \cdot \frac{1}{T} \newline

This equation is in the form of a straight line

(y = mx + c)

where:

\newline y = \ln k, \, m = -\frac{E_a}{R}, \, x = \frac{1}{T}, \, c = \ln A \newline

The slope

(m)

is negative, indicating a downward slope.

\newline

Analyzing the options:

\newline

• Option 1: The plot shows an upward slope, which is incorrect.

\newline

• Option 2: The plot shows a downward slope, which is consistent with the Arrhenius equation.

\newline

• Option 3: The plot shows an upward slope, which is incorrect.

\newline

• Option 4: The plot shows an upward slope, which is incorrect.

\newline

Therefore, the correct option is Option 2.