To find the equivalent capacitance of the given combination, we need to analyze the circuit.$\\$The circuit consists of three capacitors, each with capacitance $C. \\$Step 1: Identify the configuration of the capacitors.$\\$• The top and bottom capacitors are in parallel.$\\$• The middle capacitor is in series with the parallel combination.$\\$Step 2: Calculate the equivalent capacitance of the parallel capacitors.$\\ C_{parallel} = C + C = 2C \\$Step 3: Calculate the equivalent capacitance of the series combination.$\\$The series combination includes $C_{parallel}$ and the middle capacitor $C. \\ \frac{1}{C_{equiv}} = \frac{1}{C_{parallel}} + \frac{1}{C} \\ \frac{1}{C_{equiv}} = \frac{1}{2C} + \frac{1}{C} \\ \frac{1}{C_{equiv}} = \frac{1 + 2}{2C} \\ \frac{1}{C_{equiv}} = \frac{3}{2C} \\ C_{equiv} = \frac{2C}{3} \\$Therefore, the equivalent capacitance of the combination is $\frac{2C}{3}. \\$This corresponds to Option 2.