Kelvi

A Carnot engine has an efficiency of 50% when its source is at a temperature $327^\circ C.$ The temperature of the sink is:

medium

Thermodynamics

2023

physics

$27^\circ C$

$15^\circ C$

$100^\circ C$

$200^\circ C$

Explanation

To solve this problem, we need to use the formula for the efficiency of a Carnot engine. $\\$ The efficiency $\eta$ of a Carnot engine is given by: $\\ \eta = 1 - \frac{T_{sink}}{T_{source}} \\$

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A Carnot engine has an efficiency of 50% when its source is at a temperature 327∘C. 327^\circ C. 327∘C. The temperature of the sink is:

Explanation

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A Carnot engine has an efficiency of 50% when its source is at a temperature $327^\circ C.$ The temperature of the sink is: