To solve this problem, we need to understand Brewster's angle, which is the angle of incidence at which light with a particular polarization is perfectly transmitted through a surface, with no reflection.$\\$The Brewster's angle $i_b$ is given by the formula:$\\ \tan(i_b) = \frac{n_2}{n_1} \\$where $n_1$ is the refractive index of the first medium and $n_2$ is the refractive index of the second medium.$\\$At Brewster's angle, the reflected and refracted rays are perpendicular to each other. This means:$\\ i_b + r = 90^{\circ} \\$where $r$ is the angle of refraction.$\\$For most common interfaces, such as air to glass, the refractive index of air $(n_1)$ is approximately 1, and the refractive index of glass $(n_2)$ is around 1.5.$\\$Using the formula:$\\ \tan(i_b) = \frac{1.5}{1} = 1.5 \\$Solving for $i_b: \\ i_b = \tan^{-1}(1.5) \\$Calculating $i_b$ gives approximately $56.31^{\circ}. \\$Thus, the Brewster's angle for a typical air-glass interface is greater than $45^{\circ}$ and less than $90^{\circ}. \\$Therefore, the correct option is:$\\$Option 2: $45^{\circ} < i_b < 90^{\circ} \\$