To solve this problem, we need to understand the reaction of anisole with HI.$\\$Anisole is methoxybenzene, with the structure $$C$_6$H$_5$OCH$_3. \\$When anisole is treated with HI, the reaction involves the cleavage of the $\\$C-O bond. This is because the methyl group forms a better leaving group as $\\$methyl iodide (CH$_3$I) compared to phenyl iodide.$\\$The reaction proceeds as follows:$\\$C$_6$H$_5$OCH$_3 +$HI$\rightarrow$C$_6$H$_5$OH$+$CH$_3$I$\\$This results in phenol $(C_6{H}_5OH)$ and methyl iodide $(CH_3I). \\$Thus, the correct option is Option 4, which shows phenol and methyl iodide as the products.$\\$