To solve this problem, we need to understand the reaction of phenyl-methyl ethers with HI.$\newline$Phenyl-methyl ether is an ether with the structure: $C_6H_5-O-CH_3. \newline$When phenyl-methyl ether is treated with HI, a nucleophilic substitution reaction occurs.$\newline$The reaction proceeds as follows:$\newline C_6H_5-O-CH_3 + HI \rightarrow C_6H_5-OH + CH_3I \newline$Explanation:$\newline$• The iodine ion$(I^{-})$ attacks the less hindered methyl group $(CH_{3}),$breaking the C-O bond.$\newline$• This results in the formation of phenol$(C_6H_5OH)$ and methyl iodide $(CH_{3}I). \newline$• Phenol is the product formed from the cleavage of the ether linkage.$\newline$Analyzing the options:$\newline$• Option 1: Iodobenzene is not formed in this reaction.$\newline$• Option 2: Phenol is formed, which is correct.$\newline$• Option 3: Benzene is not formed in this reaction.$\newline$• Option 4: Ethyl chloride is not related to this reaction.$\newline$Therefore, the correct option is Option 2: Phenol.