To solve this problem, we need to understand the reaction mechanism of the given ether with HI.$\\$The given compound is an ether: $$C$_6$H$_5$CH$_2$OC$_6$H$_5. \\$When ethers react with HI, they undergo cleavage to form alcohols and alkyl iodides.$\\$Step-by-step reaction:$\\$1. Protonation of the ether oxygen:$\\$C$_6$H$_5$CH$_2$OC$_6$H$_5 +$HI$\rightarrow$C$_6$H$_5$CH$_2$OH$+$C$_6$H$_5$I$\\$2. Cleavage of the C-O bond:$\\$The bond between the benzyl group (C$_6$H$_5$CH$_2$) and the oxygen is cleaved.$\\$3. Formation of products:$\\$The benzyl group forms benzyl iodide $({C}_6{H}_5{CH}_2{I})$, and the phenyl group forms phenol $(C_6{H}_5{OH}). \\$Therefore, the products are:$\\ A =$C$_6$H$_5$CH$_2$I$\quad$and$\quad B =$C$_6$H$_5$OH$. \\$This corresponds to Option 3.