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The electron concentration in an $n$ -type semiconductor is the same as hole concentration in a $p$ -type semiconductor. An external electric field is applied across each of them. Compare the currents in them.

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Semiconductor Electronics: Material Devices and Simple Circuits

2021

physics

Current in $n$ -type $=$ Current in $p$ -type

Current in $p$ -type $>$ Current in $n$ -type

Current in $n$ -type $>$ Current in $p$ -type

No current will flow in $p$ -type $,$ current will only flow in $n$ -type

Explanation

To solve this problem, we need to compare the currents in an $n$ -type and a $p$ -type semiconductor. $\\$ Given that the electron concentration in the $n$ -type is the same as the hole concentration in the $p$ -type. $\\$ Let's denote: $\\$

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The electron concentration in an n nn-type semiconductor is the same as hole concentration in a p pp-type semiconductor. An external electric field is applied across each of them. Compare the currents in them.

Explanation

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The electron concentration in an $n$ -type semiconductor is the same as hole concentration in a $p$ -type semiconductor. An external electric field is applied across each of them. Compare the currents in them.