To solve this problem, we need to determine the structure of compound C. Let's analyze the reactions step-by-step.$\\$1. Starting compound: $C_7H_8$ is toluene, which is $C_6H_5CH_3. \\$2. Reaction with $3 \ Cl_2 / \Delta: \\$• Toluene undergoes free radical chlorination at the methyl group.$\\$• The methyl group $(CH_3)$ is converted to a trichloromethyl group $(CCl_3). \\$• Therefore, compound A is $C_6H_5CCl_3$ (benzotrichloride).$\\$3. Reaction with $Br_2/Fe: \\$• Benzotrichloride undergoes electrophilic aromatic substitution.$\\$• The bromine substitutes at the meta position relative to the $CCl_3$ group,$\\$ because the $CCl_3$ group is a strong electron-withdrawing group,$\\$ directing the incoming electrophile to the meta position.$\\$• Therefore, compound B is $m$-bromo-benzotrichloride$$ (3-bromo-1,1,1-trichlorotoluene).$\\$4. Reaction with $Zn/HCl: \\$• The $CCl_3$ group is reduced to a methyl group $(CH_3)$ by $Zn/HCl. \\$• This reduction converts the trichloromethyl group back to a methyl group.$\\$• Therefore, compound C is $m$-bromotoluene$. \\$Thus, the compound C is $m$-bromotoluene, \ which corresponds to Option 3.$\\$