To find the angle of emergence from the prism, we will use Snell's Law and the geometry of the prism.$\\$Given:$\\$• Refractive index of glass $n = \sqrt{3} \\$• Angle of prism $A = 60^{\circ} \\$Assume the angle of incidence $i = 90^{\circ}$ (since it is perpendicular to the surface).$\\$Using Snell's Law at the first surface:$\\ n_{air} \cdot \sin(i) = n_{glass} \cdot \sin(r) \\ 1 \cdot \sin(90^{\circ}) = \sqrt{3} \cdot \sin(r) \\ \sin(r) = \frac{1}{\sqrt{3}} \\ r = 30^{\circ} \\$Using the prism formula:$\\ A = r_1 + r_2 \\ 60^{\circ} = 30^{\circ} + r_2 \\ r_2 = 30^{\circ} \\$Using Snell's Law at the second surface:$\\ n_{glass} \cdot \sin(r_2) = n_{air} \cdot \sin(e) \\ \sqrt{3} \cdot \sin(30^{\circ}) = 1 \cdot \sin(e) \\ \sqrt{3} \cdot \frac{1}{2} = \sin(e) \\ \sin(e) = \frac{\sqrt{3}}{2} \\ e = 60^{\circ} \\$Therefore, the angle of emergence is $60^{\circ}. \\$This corresponds to Option 1.