To solve this problem, we need to understand the reaction of the given compound with $$Br$_2$ in the presence of FeBr$_3. \\$The compound shown is 1,2-dimethylbenzene (o-xylene). When treated with $$Br$_2$ and FeBr$_3, \\$an electrophilic aromatic substitution reaction occurs.$\\$Steps:$\\$1. The FeBr$_3$ acts as a Lewis acid and polarizes the $$Br$_2$ molecule, generating a bromonium ion $\\ ($Br$^+). \\$2. The bromonium ion acts as an electrophile and attacks the aromatic ring.$\\$3. In o-xylene, the methyl groups are ortho/para directing and activating.$\\$4. The bromination will occur at the positions ortho or para to the methyl groups.$\\$5. The possible products are 3-bromo-1,2-dimethylbenzene and 4-bromo-1,2-dimethylbenzene.$\\$Therefore, the products formed are:$\\$• 3-bromo-1,2-dimethylbenzene$\\$• 4-bromo-1,2-dimethylbenzene$\\$This corresponds to Option 3.