To solve this problem, we need to understand the concept of conduction current and displacement current in a capacitor.$\\$Given:$\\$• Capacitance $C = 20 \mu F = 20 \times 10^{-6} F \\$• Rate of change of voltage $\frac{dV}{dt} = 3$ V/s$\\$The conduction current $I_c$ through the connecting wires is given by the formula:$\\ I_c = C \cdot \frac{dV}{dt} \\$Substitute the given values:$\\ I_c = 20 \times 10^{-6} \cdot 3 \\ I_c = 60 \times 10^{-6}$ A$\\ I_c = 60 \mu A \\$The displacement current $I_d$ through the plates of the capacitor is equal to the conduction current,$\\$as per Maxwell's equations. Therefore,$\\ I_d = I_c = 60 \mu A \\$Thus, the conduction current through the connecting wires and the displacement current through the plates of the capacitor are both $60 \mu A. \\$This corresponds to Option 2.