Kelvi

A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is:

medium

Oscillations

2017

physics

$\frac{\sqrt{5}}{2\pi}$

$\frac{4 \pi}{\sqrt{5}}$

$\frac{2 \pi}{\sqrt{3}}$

$\frac{\sqrt{5}}{\pi}$

Explanation

To solve this problem, we need to use the equations of motion for simple harmonic motion (SHM). $\\$ Given: $\\$ • Amplitude $A = 3$ cm $\\$ • Displacement from mean position $x = 2$ cm $\\$

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