To determine which statement is incorrect, we need to analyze each option:$\\$Option 1: $PbF_4$ is covalent in nature.$\\$• Lead (Pb) is a heavy metal, and its compounds can exhibit both ionic and covalent characteristics.$\\$• However, due to the high electronegativity of fluorine, $PbF_4$ tends to be more ionic.$\\$• Therefore, the statement that $PbF_4$ is covalent is incorrect.$\\$Option 2: $SiCl_4$ is easily hydrolyzed.$\\$• Silicon tetrachloride (SiCl_4) is known to react readily with water, undergoing hydrolysis.$\\$• This reaction forms silicic acid and hydrochloric acid:$\\ SiCl_4 + 2H_2O \rightarrow Si(OH)_4 + 4HCl \\$• Therefore, this statement is correct.$\\$Option 3: $GeX_4$ (X = F, Cl, Br, I) is more stable than $GeX_2. \\$• Germanium (Ge) can form both $GeX_2$ and $GeX_4$ compounds.$\\$• The +4 oxidation state (GeX_4) is generally more stable than the +2 oxidation state (GeX_2) for germanium.$\\$• Therefore, this statement is correct.$\\$Option 4: $SnF_4$ is ionic in nature.$\\$• Tin (Sn) can form both ionic and covalent compounds.$\\$• Due to the high electronegativity of fluorine, $SnF_4$ tends to be more ionic.$\\$• Therefore, this statement is correct.$\\$Conclusion:$\\$The incorrect statement is Option 1: $PbF_4$ is covalent in nature.$\\$This corresponds to the correct option provided.