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Which amongst the following is an incorrect statement?
medium
Chemical bonding and Molecular structure
2022
chemistry
The bond orders of O2+,O2,O2− and O22− are 2.5, 2, 1.5 and 1, respectively.
C2 molecule has four electrons in its two degenerate π molecular orbitals.
H2+ ion has one electron.
O2+ ion is diamagnetic.
Explanation
To determine the incorrect statement, we will analyze each option step-by-step.Option 1:The bond orders of O2+,O2,O2−
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are 2.5, 2, 1.5 and 1, respectively.
• Bond order is calculated using the formula:
Bond order
=21( Number of bonding electrons
Number of antibonding electrons
• For
Electronic configuration:
(σ1s)2(σ1s∗)2(σ2s)2(σ2s∗)2(σ2pz)2(π2px)2(π2py)2(π2px∗)1(π2py∗)1 • Bond order for
O2=21(10−6)=2 • For
Remove one electron from
π2px∗ or
π2py∗ orbital.
Bond order for
O2+=21(10−5)=2.5 • For
Add one electron to
π2px∗ or
π2py∗ orbital.
Bond order for
O2−=21(10−7)=1.5 • For
O22−: Add two electrons to
π2px∗ and
π2py∗ orbitals.
Bond order for
O22−=21(10−8)=1 Thus, Option 1 is correct.
Option 2:
C
molecule has four electrons in its two degenerate
molecular orbitals.
• The electronic configuration of
is
(σ1s)2(σ1s∗)2(σ2s)2(σ2s∗)2(π2px)2(π2py)2 • The
and
orbitals are degenerate and each contains 2 electrons.
Thus, Option 2 is correct.
Option 3:
H
ion has one electron.
•
is formed by removing one electron from
leaving it with one electron.
Thus, Option 3 is correct.
Option 4:
ion is diamagnetic.
•
has an unpaired electron in the
π2px∗ or
π2py∗ orbital, making it paramagnetic.
Thus, Option 4 is incorrect.
Therefore, the incorrect statement is Option 4.