To determine which configuration has the highest net magnetic dipole moment, we need to consider the vector addition of the dipole moments. Each magnet has a magnetic dipole moment $\vec{m}. \\$Let's analyze each configuration:$\\$(a) The magnets are perpendicular to each other.$\\$• The net dipole moment is given by the vector sum:$\\ m_{net} = \sqrt{m^2 + m^2} = \sqrt{2}m \\$(b) The magnets are aligned in the same direction.$\\$• The net dipole moment is the sum of the magnitudes:$\\ m_{net} = m + m = 2m \\$(c) The magnets are at an angle of $30^\circ$ to each other.$\\$• The net dipole moment is given by:$\\ m_{net} = \sqrt{m^2 + m^2 + 2m^2 \cos(30^\circ)} \\ m_{net} = \sqrt{2m^2 + 2m^2 \cdot \frac{\sqrt{3}}{2}} \\ m_{net} = \sqrt{2m^2 + \sqrt{3}m^2} \\ m_{net} = m \sqrt{2 + \sqrt{3}} \\$(d) The magnets are at an angle of $60^\circ$ to each other.$\\$• The net dipole moment is given by:$\\ m_{net} = \sqrt{m^2 + m^2 + 2m^2 \cos(60^\circ)} \\ m_{net} = \sqrt{2m^2 + 2m^2 \cdot \frac{1}{2}} \\ m_{net} = \sqrt{2m^2 + m^2} \\ m_{net} = m \sqrt{3} \\$Comparing the net dipole moments:$\\$• Configuration (a): $\sqrt{2}m \\$• Configuration (b): $2m \\$• Configuration (c): $m \sqrt{2 + \sqrt{3}} \\$• Configuration (d): $m \sqrt{3} \\$Since $\sqrt{2 + \sqrt{3}} > 2$, configuration (c) has the highest net magnetic dipole moment.$\\$Therefore, the correct option is (c).