Kelvi

Consider the change in oxidation state of Bromine corresponding to different emf values as shown in the diagram below: $\newline BrO_4^{-} \xrightarrow{1.82V} BrO_4^{-} \xrightarrow{1.5V} HBrO \xrightarrow{1.595V}Br_2\xrightarrow{1.0652V} Br^- \\$ Then the species undergoing disproportionation is

hard

RedoxReactions

2018

chemistry

Br $_2$

BrO $_4^-$

BrO $_3^-$

Explanation

To determine which species undergoes disproportionation, we need to analyze the oxidation states of Bromine in each species and the corresponding emf values. $\\$ The given reactions are: $\\$ 1. BrO $_4^- \xrightarrow{1.82V}$

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