To find the wavelength of the electromagnetic radiation emitted by the transmitter, we use the relationship between speed, frequency, and wavelength:$\\ c = \nu \lambda \\$where:$\\$• $c$ is the speed of light, $3.0 \times 10^8$ m/s$\\$• $\nu$ is the frequency of the radio wave, $1368$ kHz$\\$• $\lambda$ is the wavelength in meters$\\$First, convert the frequency from kilohertz to hertz:$\\ \nu = 1368 \times 10^3$ Hz$\\$Now, rearrange the formula to solve for wavelength $\lambda: \\ \lambda = \frac{c}{\nu} \\$Substitute the known values:$\\ \lambda = \frac{3.0 \times 10^8}{1368 \times 10^3} \\$Calculate the wavelength:$\\ \lambda = \frac{3.0 \times 10^8}{1.368 \times 10^6} \\ \lambda = 219.2982456$ m$\\$Rounding to one decimal place, the wavelength is approximately $219.3$ m.$\\$Therefore, the correct option is Option 1: $219.3$ m.