To solve this problem, we need to identify compound A and Y based on the given reaction.$\newline$The reaction involves compound A, $C_8H_{10}O,$ reacting with NaOI to yield a yellow precipitate with a characteristic smell.$\newline$This is indicative of the iodoform test, which is positive for methyl ketones or alcohols with the structure $R-CH(OH)-CH_3. \newline$The yellow precipitate is iodoform (CHI$_3$), which has a characteristic smell.$\newline$NaOI is produced by reacting iodine (I$_2$) with NaOH.$\newline$Let's analyze the options:$\newline$Option 1:$$ A is $$C$_6$H$_5$CH(OH)CH$_3$ (a secondary alcohol)$$ and Y is $$I$_2. \newline$• This compound fits the criteria for a positive iodoform test.$\newline$Option 2:$$ A is $$C$_6$H$_5$CH$_2$CH$_2$OH$$ and Y is $$I$_2. \newline$• This compound does not have the required structure for a positive iodoform test.$\newline$Option 3:$$ A is $$C$_6$H$_4$CH$_2$OH$$ and Y is $$I$_2. \newline$• This compound does not have the required structure for a positive iodoform test.$\newline$Option 4:$$ A is $$C$_6$H$_4($CH$_3)_2$OH$$ and Y is $$I$_2. \newline$• This compound does not have the required structure for a positive iodoform test.$\newline$Therefore, the correct option is Option 1, where A is $$C$_6$H$_5$CH(OH)CH$_3$ and Y is $$I$_2.$