To determine the order of osmotic pressure for the given solutions, we need to use the formula for osmotic pressure:$\\ \Pi = i \cdot C \cdot R \cdot T \\$Where:$\\$• $\Pi$ is the osmotic pressure.$\\$• $i$ is the van 't Hoff factor (number of particles the solute dissociates into).$\\$• $C$ is the molar concentration of the solution.$\\$• $R$ is the ideal gas constant.$\\$• $T$ is the temperature in Kelvin.$\\$Since all solutions are prepared in the same volume of water (250 ml), and assuming the temperature is constant,$\\$the osmotic pressure is directly proportional to the product of the van 't Hoff factor and the molar concentration:$\\ \Pi \propto i \cdot C \\$Let's calculate the molar concentration for each solution:$\\$1. For glucose $(C_6H_{12}O_6): \\$Molar mass of glucose $= 180 \, \mathrm{g/mol} \\$Moles of glucose $= \frac{10 \, \mathrm{g}}{180 \, \mathrm{g/mol}} = \frac{1}{18} \, \mathrm{mol} \\$Concentration $C_1 = \frac{\frac{1}{18} \, \mathrm{mol}}{0.250 \, \mathrm{L}} = \frac{1}{4.5} \, \mathrm{mol/L} \\$Van 't Hoff factor $i_1 = 1$ (glucose does not dissociate)$\\$2. For urea $(CH_4N_2O): \\$Molar mass of urea $= 60 \, \mathrm{g/mol} \\$Moles of urea $= \frac{10 \, \mathrm{g}}{60 \, \mathrm{g/mol}} = \frac{1}{6} \, \mathrm{mol} \\$Concentration $C_2 = \frac{\frac{1}{6} \, \mathrm{mol}}{0.250 \, \mathrm{L}} = \frac{2}{3} \, \mathrm{mol/L} \\$Van 't Hoff factor $i_2 = 1$ (urea does not dissociate)$\\$3. For sucrose $(C_{12}H_{22}O_{11}): \\$Molar mass of sucrose $= 342 \, \mathrm{g/mol} \\$Moles of sucrose $= \frac{10 \, \mathrm{g}}{342 \, \mathrm{g/mol}} = \frac{5}{171} \, \mathrm{mol} \\$Concentration $C_3 = \frac{\frac{5}{171} \, \mathrm{mol}}{0.250 \, \mathrm{L}} = \frac{20}{171} \, \mathrm{mol/L} \\$Van 't Hoff factor $i_3 = 1$ (sucrose does not dissociate)$\\$Now, calculate the osmotic pressure for each solution:$\\ \Pi_1 \propto i_1 \cdot C_1 = 1 \cdot \frac{1}{4.5} = \frac{1}{4.5} \\ \Pi_2 \propto i_2 \cdot C_2 = 1 \cdot \frac{2}{3} = \frac{2}{3} \\ \Pi_3 \propto i_3 \cdot C_3 = 1 \cdot \frac{20}{171} = \frac{20}{171} \\$Comparing the values:$\\ \frac{2}{3} > \frac{1}{4.5} > \frac{20}{171} \\$Thus, the decreasing order of osmotic pressure is:$\\ P_2 > P_1 > P_3 \\$Therefore, the correct option is Option 1.