To solve this problem, we need to determine the limit of resolution of a telescope.$\\$The limit of resolution for a telescope is given by the formula:$\\ \theta = \frac{1.22 \lambda}{D} \\$where:$\\$• $\theta$ is the angular resolution (limit of resolution).$\\$• $\lambda$ is the wavelength of light.$\\$• $D$ is the diameter of the telescope's objective.$\\$Given:$\\$• Wavelength $\lambda = 600$ nm$= 600 \times 10^{-9}$ m$\\$• Diameter $D = 2$ m$\\$Substitute the known values into the formula:$\\ \theta = \frac{1.22 \times 600 \times 10^{-9}}{2} \\$Calculate:$\\ \theta = \frac{732 \times 10^{-9}}{2} \\ \theta = 366 \times 10^{-9}$ rad$\\ \theta = 3.66 \times 10^{-7}$ rad$\\$Therefore, the limit of resolution of the telescope is $3.66 \times 10^{-7}$ rad.$\\$This corresponds to Option 4.