To solve this problem, we need to find the temperature coefficient of resistance, denoted as $\alpha. \\$The formula for resistance as a function of temperature is:$\\ R_T = R_0 (1 + \alpha \Delta T) \\$Where:$\\$• $R_T$ is the resistance at temperature $T. \\$• $R_0$ is the resistance at the reference temperature (usually 0°C).$\\$• $\alpha$ is the temperature coefficient of resistance.$\\$• $\Delta T$ is the change in temperature.$\\$Given:$\\$• $R_0 = 2 \, \Omega$ at $0°C. \\$• $R_T = 6.8 \, \Omega$ at $80°C. \\$• $\Delta T = 80°C - 0°C = 80°C. \\$Substitute the known values into the formula:$\\ 6.8 = 2 (1 + \alpha \times 80) \\$Divide both sides by 2 to isolate the term with $\alpha: \\ 3.4 = 1 + 80\alpha \\$Subtract 1 from both sides:$\\ 2.4 = 80\alpha \\$Solve for $\alpha: \\ \alpha = \frac{2.4}{80} \\ \alpha = 0.03 \\$Convert $\alpha$ to scientific notation:$\\ \alpha = 3 \times 10^{-2} \, °C^{-1} \\$Therefore, the temperature coefficient of resistance is $3 \times 10^{-2} \, °C^{-1}. \\$This corresponds to Option 3.