Kelvi

Kelvi

Earn up to ₹2000

0 pts

27days until NEET 2026Every question counts. ✊

🌿

Did you know?

A single strand of DNA, if uncoiled, would be ~6 feet long — yet it fits inside a cell nucleus.

Kelvi

Earn up to ₹2000

0 pts

Which is the correct thermal stability order for $H_2E$ (E = O, S, Se, Te and Po)?

medium

Chemical bonding and Molecular structure

2019

chemistry

$H_2S < H_2O < H_2Se < H_2Te < H_2Po$

$H_2O < H_2S < H_2Se < H_2Te < H_2Po$

$H_2Po < H_2Te < H_2Se < H_2S < H_2O$

$H_2Se < H_2Te < H_2Po < H_2O < H_2S$

Explanation

To determine the thermal stability order of $H_2E$ (where $E = O, S, Se, Te,$ and $Po), \\$

Our AI powered practice platform can help you achieve your doctor dream.

Practice 2000+ previous year NEET questions
More practice, more score
AI generated hints
Use hints to get start solving
AI companion chat to clear doubts 24*7
Ask any question, get instant answers
AI generated solutions
Get detailed step by step solutions
Check related NCERT content
Read while solving
Track your progress
Improve every day

Sign up / Login

we need to consider the bond strength between hydrogen and the chalcogen (E).

\\

The thermal stability of these hydrides is primarily influenced by the bond dissociation energy.

\\

As we move down the group in the periodic table, the size of the chalcogen atom increases.

\\

This leads to a decrease in bond strength due to poorer overlap between the hydrogen 1s orbital

\\

and the larger, more diffuse orbitals of the heavier chalcogens.

\\

Therefore, the bond strength decreases as we move from

H_2O

to

H_2Po. \\

This results in a decrease in thermal stability in the same order.

\\

Thus, the correct thermal stability order is:

\\ H_2Po < H_2Te < H_2Se < H_2S < H_2O \\

This corresponds to Option 3.