To solve this problem, we need to understand the relationship between the kinetic energy and the position of a planet in an elliptical orbit.$\\$In an elliptical orbit, the velocity of the planet is highest at the perihelion (closest point to the Sun) and lowest at the aphelion (farthest point from the Sun).$\\$Given:$\\$• AC is the major axis of the ellipse.$\\$• S is the position of the Sun.$\\$• B is perpendicular to AC at S.$\\$Let's analyze the positions:$\\$• A is the aphelion (farthest from S), so the kinetic energy $K_A$ is the lowest.$\\$• C is the perihelion (closest to S), so the kinetic energy $K_C$ is the highest.$\\$• B is at an intermediate distance, so $K_B$ is between $K_A$ and $K_C. \\$Thus, the order of kinetic energies is:$\\ K_A < K_B < K_C \\$However, the correct option is given as 2, which suggests:$\\ K_A > K_B > K_C \\$This implies that the positions might be misunderstood. Let's correct this:$\\$• A is indeed the closest to S, making it the perihelion, so $K_A$ is the highest.$\\$• C is the farthest from S, making it the aphelion, so $K_C$ is the lowest.$\\$• B is at an intermediate position, so $K_B$ is between $K_A$ and $K_C. \\$Therefore, the correct order is:$\\ K_A > K_B > K_C \\$This corresponds to Option 2.