To solve this problem, we need to determine which compound will be most readily dehydrated under acidic conditions.$\newline$Dehydration of alcohols typically involves the formation of a carbocation intermediate. The stability of this intermediate is crucial.$\newline$The more stable the carbocation, the more readily the alcohol will dehydrate.$\newline$Let's analyze each option:$\newline$• Option 1: The alcohol is secondary, and the presence of the $NO_2$ group is electron-withdrawing, which destabilizes the carbocation.$\newline$• Option 2: The alcohol is secondary, and there is a possibility of forming a stable carbocation due to the presence of another hydroxyl group nearby.$\newline$• Option 3: Similar to Option 1, the $NO_2$ group is electron-withdrawing, making the carbocation less stable.$\newline$• Option 4: The alcohol is primary, and the $NO_2$ group is electron-withdrawing, leading to a less stable carbocation.$\newline$Option 2 is the most favorable for dehydration because the formation of a stable carbocation is facilitated by the adjacent hydroxyl group.$\newline$Therefore, the compound in Option 2 will be most readily dehydrated under acidic conditions.$\newline$This corresponds to the correct option: Option 2.