To solve this problem, we need to understand the reaction of an alkyne with $$KMnO$_4/$H$^+. \\$This is an oxidative cleavage reaction where the alkyne is cleaved to form carboxylic acids.$\\$Given reaction:$\\$Cyclohexylacetylene (C$\equiv$C-H) reacts with $$KMnO$_4/$H$^+. \\$Steps:$\\$1. The triple bond in the alkyne is oxidatively cleaved by $$KMnO$_4/$H$^+. \\$2. Each carbon of the triple bond is converted into a carboxylic acid group.$\\$For the given compound:$\\$• The alkyne group is attached to a cyclohexyl group on one side and a hydrogen on the other.$\\$• Oxidative cleavage will convert the alkyne into two carboxylic acids:$\\$ - The carbon attached to the cyclohexyl group becomes cyclohexanecarboxylic acid.$\\$ - The terminal carbon (attached to hydrogen) becomes formic acid, which further oxidizes to $$CO$_2$ and $$H$_2$O.$\\$Thus, the major product $'P'$ is cyclohexanecarboxylic acid.$\\$Therefore, the correct option is Option 4:$\\$Cyclohexanecarboxylic acid (Cyclohexane-COOH).