To solve this problem, we need to determine the radius of one atom in a cubic unit cell.$\newline$Given:$\newline$• The metal crystallizes with a cubic structure.$\newline$• Edge length of the unit cell $= 361 \,$pm.$\newline$• There are four metal atoms in one unit cell.$\newline$This indicates that the metal has a face-centered cubic (FCC) structure.$\newline$In an FCC structure, the relation between the edge length $(a)$ and the atomic radius $(r)$ is:$\newline a = 2\sqrt{2}r \newline$Substitute the given edge length:$\newline 361 = 2\sqrt{2}r \newline$Solve for $r: \newline r = \frac{361}{2\sqrt{2}} \newline r = \frac{361}{2 \times 1.414} \newline r \approx \frac{361}{2.828} \newline r \approx 127.7 \,$pm$\newline$Therefore, the radius of one atom is approximately $127 \,$pm.$\newline$This corresponds to Option 1.