To solve this problem, we need to analyze the reaction sequence step-by-step:$\newline$1. The first reaction involves the conversion of an alcohol to an alkyl bromide using $PBr_3. \newline$• The given compound is a cyclohexanol derivative.$\newline$• $PBr_3$ replaces the $OH$ group with a $Br$ atom.$\newline$• This results in the formation of a bromo compound, which is compound A.$\newline$2. The second reaction involves the elimination reaction using alcoholic KOH.$\newline$• Alcoholic KOH induces dehydrohalogenation, removing $HBr$ to form an alkene.$\newline$• The major product is the more substituted alkene due to Saytzeff's rule.$\newline$Analyzing the options:$\newline$• Option 1: Incorrect, as the product B is not an alkene.$\newline$• Option 2: Incorrect, as the product B is a ketone, not formed in this reaction.$\newline$• Option 3: Correct, as A is the bromo compound and B is the more substituted alkene.$\newline$• Option 4: Incorrect, as the alkene is less substituted.$\newline$Therefore, the correct option is Option 3.$\newline$Compound A: $$1-bromo-2-methylcyclohexane$\newline$Compound B: $$3-methylcyclohexene