To solve this problem, we need to understand the potential difference between two points on a charged spherical shell.$\\$Given:$\\$• Charge on the shell $q = 1 \mu C = 1 \times 10^{-6} C \\$• Radius of the shell $R = 3$ cm$= 0.03$ m$\\$• $\frac{1}{4\pi \varepsilon_0} = 9 \times 10^9$ SI units$\\$For a charged spherical shell, the potential at any point inside the shell is constant and equal to the potential on the surface.$\\$The potential $V$ at any point inside or on the surface of the shell is given by:$\\ V = \frac{1}{4\pi \varepsilon_0} \cdot \frac{q}{R} \\$Substitute the given values:$\\ V = 9 \times 10^9 \cdot \frac{1 \times 10^{-6}}{0.03} \\ V = 9 \times 10^9 \cdot \frac{1}{3} \times 10^{-5} \\ V = 3 \times 10^5$ V$\\$Since both points C and P are inside the shell, the potential at both points is the same.$\\$Therefore, the potential difference between C and P is zero.$\\$This corresponds to Option 2: Zero.