Did you know?
One mole contains 6.022 × 10²³ particles — if a mole of seconds passed, it'd be 19 quadrillion years.
Did you know?
One mole contains 6.022 × 10²³ particles — if a mole of seconds passed, it'd be 19 quadrillion years.
To solve this problem, we need to determine the percentages of the other three bases in sea urchin DNA, given that 17% of the bases are cytosine (C).According to Chargaff's rules for double-stranded DNA:The amount of adenine (A) is equal to the amount of thymine (T).The amount of cytosine (C) is equal to the amount of guanine (G).Given that C = 17%, it follows that G = 17% as well.Since the total percentage of all four bases must equal 100%, we can write:C + G + A + T = 100%Substituting the known values:This simplifies to:Since A = T, we can divide the remaining percentage equally between A and T:Therefore, the percentages of the bases are:G = 17%A = 33%T = 33%This corresponds to Option 3: G 17%, A 33%, T 33%.
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