To solve this problem, we need to understand the reaction of D-(+)-glucose with hydroxylamine.$\newline$• D-(+)-glucose is an aldohexose, meaning it contains an aldehyde group at the first carbon.$\newline$• Hydroxylamine (NH$_2$OH) reacts with the aldehyde group to form an oxime.$\newline$The reaction can be represented as:$\newline$Aldehyde group: $CHO + NH_2OH \rightarrow CH=NOH \newline$• The rest of the glucose structure remains unchanged.$\newline$Let's analyze the options:$\newline$Option 1: The oxime is formed at the first carbon, but the configuration is incorrect.$\newline$Option 2: The oxime is correctly formed at the first carbon, and the configuration matches D-(+)-glucose.$\newline$Option 3: The oxime is formed at the first carbon, but the configuration is incorrect.$\newline$Option 4: The oxime is formed at the first carbon, but the configuration is incorrect.$\newline$Therefore, the correct structure of the oxime is given in Option 2.