To solve this problem, we need to understand the reaction taking place.$\\$The given reaction involves the reduction of a compound using $\mathrm{NaBH_4}$ in $\mathrm{C_2H_5OH}. \\$Let's analyze the structure of the reactant:$\\$• The reactant has two carbonyl groups: a ketone and an ester.$\\$Sodium borohydride (NaBH$_4$) is a selective reducing agent that typically reduces aldehydes and ketones,$\\$but not esters under normal conditions.$\\$Therefore, in this reaction, only the ketone group will be reduced to an alcohol.$\\$Let's identify the product:$\\$• The ketone group in the cyclohexane ring will be reduced to a secondary alcohol.$\\$• The ester group will remain unchanged.$\\$Now, let's compare with the options:$\\$Option 1: Both the ketone and ester are reduced, which is incorrect.$\\$Option 2: The ester is reduced, which is incorrect.$\\$Option 3: Both the ketone and ester are reduced, which is incorrect.$\\$Option 4: Only the ketone is reduced, which is correct.$\\$Therefore, the correct product is shown in Option 4.