Kelvi

Kelvi

0 pts

0days until NEET 2026Every question counts. ✊

🌡️

Did you know?

Absolute zero (−273.15°C) is the coldest possible temperature — at which atoms nearly stop moving.

Kelvi

0 pts

In the given nuclear reaction, the element X is: $\newline$ $^{22}_{11} Na \rightarrow X + e^{+} + {v}$

medium

Nuclei

2022

physics

$^{23}_{11} Na$

$^{23}_{10} Ne$

Explanation

To solve this problem, we need to analyze the given nuclear reaction: $\\ ^{22}_{11}$ Na $\rightarrow X + e^{+} + v \\$

Our AI powered practice platform can help you achieve your doctor dream.

Practice 2000+ previous year NEET questions
More practice, more score
AI generated hints
Use hints to get start solving
AI companion chat to clear doubts 24*7
Ask any question, get instant answers
AI generated solutions
Get detailed step by step solutions
Check related NCERT content
Read while solving
Track your progress
Improve every day

Sign up / Login

$^{22}_{10} Ne$

$^{22}_{12} Mg$

This reaction is a beta-plus decay, where a proton in the nucleus is converted into a neutron,

\\

emitting a positron

(e^{+})

and a neutrino

(v). \\

In beta-plus decay, the atomic number decreases by 1, while the mass number remains unchanged.

\\

Given:

\\

• Initial element:

^{22}_{11}

Na

\\

• Final element:

X \\

Since the mass number remains the same, the mass number of

X

is 22.

\\

The atomic number of

X

is

11 - 1 = 10. \\

Therefore,

X

is

^{22}_{10}

Ne

. \\

This corresponds to Option 3.