To solve this problem, we need to analyze the elimination reaction of 2-Bromo-pentane to form pent-2-ene.$\newline$Let's break down the reaction and the options provided:$\newline$1. The reaction involves the elimination of a hydrogen halide (HBr) from 2-Bromo-pentane.$\newline$2. This type of reaction is known as a $\beta$-elimination reaction because the hydrogen is removed from the $\beta$-carbon.$\newline$3. The reaction follows Zaitsev's rule, which states that the more substituted alkene is the major product.$\newline$ In this case, pent-2-ene is more substituted than pent-1-ene, so it is the major product.$\newline$4. The reaction is also a dehydrohalogenation reaction, as it involves the removal of HBr.$\newline$5. Dehydration reactions typically refer to the removal of water, which is not the case here.$\newline$Analyzing the options:$\newline$• Option (a): $\beta$-Elimination reaction is correct.$\newline$• Option (b): Follows Zaitsev rule is correct.$\newline$• Option (c): Dehydrohalogenation reaction is correct.$\newline$• Option (d): Dehydration reaction is incorrect.$\newline$Therefore, the correct combination of options is:$\newline$Option 4: (a), (b), (c).