Kelvi

A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to: $v(x) = \beta x^{-2n}$ where $\beta$ and $n$ are constants and $x$ is the position of the particle. The acceleration of the particle as a function of $x$ is given by

hard

Motion in a Plane

2015

physics

$-2n\beta^2 x^{-4n-1}$

$-2\beta^2 x^{-2n+1}$

Explanation

To find the acceleration of the particle as a function of $x,$ we start with the given velocity function: $\\ v(x) = \beta x^{-2n} \\$ The acceleration $a(x)$

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