To solve this problem, we need to determine the relationship between the minimum wavelength of X-rays and the potential difference through which electrons are accelerated.$\\$The minimum wavelength $\lambda_{min}$ of X-rays is given by the equation:$\\ \lambda_{min} = \frac{hc}{eV} \\$where:$\\$• $h$ is Planck's constant,$\\$• $c$ is the speed of light,$\\$• $e$ is the charge of an electron,$\\$• $V$ is the potential difference in volts.$\\$From the equation, we can see that $\lambda_{min}$ is inversely proportional to the potential difference $V. \\$Therefore, the minimum wavelength of X-rays is proportional to $\frac{1}{V}. \\$This corresponds to Option 2.