To solve this problem, we need to identify the major product C formed in the given reaction sequence.$\newline$The sequence is:$\newline CH_3-CH_2-CH_2-I \xrightarrow{NaCN} A \xrightarrow[partial\ hydrolysis]{OH^-} B \xrightarrow[Br_2]{NaOH} C \ (major) \newline$Let's analyze each step:$\newline$1. The first step involves the reaction of 1-iodopropane with sodium cyanide (NaCN):$\newline$• This is a nucleophilic substitution reaction where the iodide ion is replaced by the cyanide ion.$\newline$• The product A is propanenitrile (CH_3-CH_2-CH_2-CN).$\newline$2. The second step is the partial hydrolysis of propanenitrile:$\newline$• Under basic conditions (OH^-), the nitrile group (-CN) is partially hydrolyzed to form a carboxylate ion.$\newline$• The product B is propanoic acid (CH_3-CH_2-COOH).$\newline$3. The third step is the Hofmann bromamide reaction:$\newline$• Propanoic acid is treated with bromine and sodium hydroxide.$\newline$• This reaction converts the carboxylic acid into an amine with one less carbon atom.$\newline$• The product C is propylamine (CH_3-CH_2-CH_2-NH_2).$\newline$Analyzing the options:$\newline$• Option 1: Butanamide is incorrect as it has one more carbon than propylamine.$\newline$• Option 2: α-Bromobutanoic acid is incorrect as it is not an amine.$\newline$• Option 3: Propylamine is correct as it matches the product C.$\newline$• Option 4: Butylamine is incorrect as it has one more carbon than propylamine.$\newline$Therefore, the correct option is Option 3: Propylamine.