To solve this problem, we will use Wien's Displacement Law, which states that the wavelength at which the intensity of radiation is maximum is inversely proportional to the absolute temperature of the black body.$\\$Mathematically, it is given by:$\\ \lambda_{max} \cdot T = b \\$where $\lambda_{max}$ is the wavelength of maximum intensity, $T$ is the absolute temperature, and $b$ is Wien's constant.$\\$Given:$\\$• Star P has maximum intensity in violet light.$\\$• Star R has maximum intensity in green light.$\\$• Star Q has maximum intensity in red light.$\\$The approximate wavelengths for these colors are:$\\$• Violet: $\lambda_{V} \approx 400 \,$nm$\\$• Green: $\lambda_{G} \approx 550 \,$nm$\\$• Red: $\lambda_{R} \approx 700 \,$nm$\\$According to Wien's Law, the star with the shortest $\lambda_{max}$ will have the highest temperature.$\\$Therefore, we can conclude:$\\$• $T_P > T_R > T_Q$ because $\lambda_{V} < \lambda_{G} < \lambda_{R}. \\$Thus, the correct order of temperatures is:$\\ T_P > T_Q > T_R \\$This corresponds to Option 4.