To solve this problem, we need to analyze the reaction between phthalic acid and ammonia under strong heating.$\newline$Phthalic acid is a benzene ring with two adjacent carboxylic acid groups.$\newline$When phthalic acid is heated strongly with ammonia, it undergoes a cyclization reaction.$\newline$Here's the step-by-step mechanism:$\newline$1. Formation of Ammonium Phthalate:$\newline$• The carboxylic acid groups react with ammonia to form ammonium phthalate.$\newline$2. Cyclization to Form Phthalimide:$\newline$• Upon strong heating, the ammonium phthalate loses water molecules.$\newline$• This results in the formation of a cyclic imide, specifically phthalimide.$\newline$• The reaction involves the formation of a five-membered ring.$\newline$Analyzing the options:$\newline$• Option 1: Contains an amide and a carboxylic acid, which is incorrect.$\newline$• Option 2: Shows phthalimide, which is the correct product.$\newline$• Option 3: Contains an amine and a carboxylic acid, which is incorrect.$\newline$• Option 4: Contains two amine groups, which is incorrect.$\newline$Therefore, the correct option is Option 2, which corresponds to the formation of phthalimide.