To solve this problem, we need to analyze the behavior of the diode in the given circuit.$\\$The input is a square wave signal oscillating between $+5 \,$V and $-5 \,$V.$\\$1. When the input is $+5 \,$V:$\\$• The diode is forward-biased, allowing current to pass through.$\\$• The output across $R_L$ will be approximately $+5 \,$V (assuming ideal diode with no voltage drop).$\\$2. When the input is $-5 \,$V:$\\$• The diode is reverse-biased, blocking current flow.$\\$• The output across $R_L$ will be $0 \,$V.$\\$Thus, the output waveform across $R_L$ will be a rectified signal, only allowing the positive half-cycles.$\\$The output will be a square wave oscillating between $0 \,$V and $+5 \,$V.$\\$This corresponds to Option 3, which shows a waveform with a peak of $5 \,$V.$\\$Therefore, the correct option is Option 3.