To solve this problem, we will use the kinematic equations for uniformly accelerated motion.$\\$Given:$\\$• Initial velocity $u = 20$ m/s (downward)$\\$• Final velocity $v = 80$ m/s (downward)$\\$• Acceleration due to gravity $g = 10$ m/s$^2 \\$We need to find the height of the tower, $h. \\$Using the kinematic equation:$\\ v^2 = u^2 + 2gh \\$Substitute the known values:$\\ 80^2 = 20^2 + 2 \cdot 10 \cdot h \\$Simplify:$\\ 6400 = 400 + 20h \\$Rearrange to solve for $h: \\ 20h = 6400 - 400 \\ 20h = 6000 \\ h = \frac{6000}{20} \\ h = 300 \\$Therefore, the height of the tower is $300$ m. This corresponds to Option 3.