To solve this problem, we need to determine the fractional compression of water at the bottom of the ocean.$\\$The formula for fractional compression is given by:$\\ \Delta V/V = -\beta \Delta P \\$where:$\\$• $\Delta V/V$ is the fractional change in volume (compression),$\\$• $\beta$ is the compressibility of water,$\\$• $\Delta P$ is the change in pressure.$\\$The change in pressure $\Delta P$ at the bottom of the ocean can be calculated using:$\\ \Delta P = \rho g h \\$where:$\\$• $\rho = 10^3$ kg m$^{-3}$ is the density of water,$\\$• $g = 9.8$ m s$^{-2}$ is the acceleration due to gravity,$\\$• $h = 2700$ m is the depth of the ocean.$\\$Substitute the values into the pressure change equation:$\\ \Delta P = 10^3 \times 9.8 \times 2700 \\ \Delta P = 2.646 \times 10^7$ Pa$\\$Now, substitute $\Delta P$ and $\beta = 45.4 \times 10^{-11}$ Pa$^{-1}$ into the fractional compression formula:$\\ \Delta V/V = - (45.4 \times 10^{-11}) \times (2.646 \times 10^7) \\ \Delta V/V = -1.201 \times 10^{-2} \\$The negative sign indicates compression. Therefore, the fractional compression of water is approximately $1.2 \times 10^{-2}. \\$This corresponds to Option 2.